Calculating RC time constants...and why you should.
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Calculating RC time constants...and why you should.
One of the most important things to consider when tweaking amps is the interaction between resistors and capacitors. In series or parallel with each other they do particular frequency dependant things.
One thing they do depending on orientation (high pass filter, low pass filter, parallel) is create a cutoff frequency. In guitar amps, this is illustrated by the cathode cap and resistor. Their value determines at which frequency a 6db per octave rolloff happens at.
The formula to find that frequency is:
F= 1
--------------
(2 pi) R C
For your typical .68/2.7k combination the formula is this:
F= 1
------------------------------- = 87Hz
6.28 * .00000068 * 2,700
Meaning that every frequency above 88Hz is at full gain for that stage.
For the 470pf/470k mix resistor arrangement, it works out like this:
F= 1
------------------------------------ = 720 Hz
6.28 * 00000000047 * 470,000
Meaning that every frequency below 737 rolls off at a 6db per octave slope.
You can also calculate the frequency determined by coupling caps and the equivalent resistance in the circuit. In the first stage of a Marshall you have a .022 or a .0022 with a 100k plate resistor and 1M to ground via the volume pot. Your equivalent circuit resistance is 91k. Making the formula:
F= 1
-------------------------------- = 80Hz for a .022uf
6.28 * .000000022 * 91,000
F= 1
---------------------------------- = 795Hz for a .0022uf
6.28 * .0000000022 * 91,000
Doesn't that explain why a .022 sounds so much fuller?
I hope this formula will shed some light on what's happening frequency wise in amplifiers. And hopefully we can use this to achieve our desired tones.
George
One thing they do depending on orientation (high pass filter, low pass filter, parallel) is create a cutoff frequency. In guitar amps, this is illustrated by the cathode cap and resistor. Their value determines at which frequency a 6db per octave rolloff happens at.
The formula to find that frequency is:
F= 1
--------------
(2 pi) R C
For your typical .68/2.7k combination the formula is this:
F= 1
------------------------------- = 87Hz
6.28 * .00000068 * 2,700
Meaning that every frequency above 88Hz is at full gain for that stage.
For the 470pf/470k mix resistor arrangement, it works out like this:
F= 1
------------------------------------ = 720 Hz
6.28 * 00000000047 * 470,000
Meaning that every frequency below 737 rolls off at a 6db per octave slope.
You can also calculate the frequency determined by coupling caps and the equivalent resistance in the circuit. In the first stage of a Marshall you have a .022 or a .0022 with a 100k plate resistor and 1M to ground via the volume pot. Your equivalent circuit resistance is 91k. Making the formula:
F= 1
-------------------------------- = 80Hz for a .022uf
6.28 * .000000022 * 91,000
F= 1
---------------------------------- = 795Hz for a .0022uf
6.28 * .0000000022 * 91,000
Doesn't that explain why a .022 sounds so much fuller?
I hope this formula will shed some light on what's happening frequency wise in amplifiers. And hopefully we can use this to achieve our desired tones.
George
Last edited by VelvetGeorge on Wed Apr 20, 2005 12:42 pm, edited 1 time in total.
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OUCH! All this math and formulas...my brain Hertz!
Actually, it did shed some light on something. The hard rock tone I've noticed centers around 700-800Hz, which I believe produces that midrange "squawk" tone you get with a lot of false harmonics(very common in the 80's, ala Warren DiMartini from Ratt). The .0022uF/1M/100K arrangement and the 470K/470pF arrangement definitely explains why it's easy to get that on Marshalls.
However, it kills me when people are like "well, since 82.41Hz is the frequency of the low E string, there's nothing below that that is essential to the guitar". But how can that be? Yeah, sure the FUNDAMENTAL frequency of the low E string is 82.41Hz, provided you're in standard tuning, however certain players(like George) are known to tune down 1/2 step, and on top of that, people forget that strings don't just produce the fundamental note, they also produce harmonics that are above and below the fundamental frequency. These harmonics are what make a guitar sound like a guitar. In order to achieve great tone one must take these factors into account.
Jon
Actually, it did shed some light on something. The hard rock tone I've noticed centers around 700-800Hz, which I believe produces that midrange "squawk" tone you get with a lot of false harmonics(very common in the 80's, ala Warren DiMartini from Ratt). The .0022uF/1M/100K arrangement and the 470K/470pF arrangement definitely explains why it's easy to get that on Marshalls.
However, it kills me when people are like "well, since 82.41Hz is the frequency of the low E string, there's nothing below that that is essential to the guitar". But how can that be? Yeah, sure the FUNDAMENTAL frequency of the low E string is 82.41Hz, provided you're in standard tuning, however certain players(like George) are known to tune down 1/2 step, and on top of that, people forget that strings don't just produce the fundamental note, they also produce harmonics that are above and below the fundamental frequency. These harmonics are what make a guitar sound like a guitar. In order to achieve great tone one must take these factors into account.
Jon
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Thats like stereo manufacturers that concentrate a lot on sub-audio levels. People say "if we cant hear those frequencies anyway why waste time on them" but they do make a difference in the final tone. Too many and the bass gets out of control even if we dont percieve that much bass in the signal. Shit. Thats like saying just because the A string is 440hz cutting off all the bass below that wont effect the A string. Yeah right...
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And that's due to the harmonics below the string's fundamental frequency. But NO...those aren't important remember?
ANd actually, 440Hz is the frequency of the high A fretted at the 5th fret high E string, the 10th fret B string(2nd), the 14th fret G string(uh...huh...huh...hhe said G string), the 19th fret D string(4th), and for those of us with 24 fret necks, the 24th fret A string(5th).WOW! So on a 24 fret neck, there's 5 places to hit the same note! However the thing most people don't realize is that in each of those positions the note has a much different tone voicing, becoming brighter closer to the top of the neck and darker closer to the body.
However, 440Hz is the standard tuning note for all instruments. This is the A note you hear large orchestras tuning to. But basically, the rule is that the frequency of a note doubles every octave. So 110Hz being the low A, the middle A on the second fret G and the 7th fret D, or the 12th fret A is 220Hz, and the next one up is 440Hz.
So on a 24 fret guitar, the highest E note would be 1318.56Hz, or 1.3KHz, so this means that boosting any frequencies above that won't make a difference right?
Jon
ANd actually, 440Hz is the frequency of the high A fretted at the 5th fret high E string, the 10th fret B string(2nd), the 14th fret G string(uh...huh...huh...hhe said G string), the 19th fret D string(4th), and for those of us with 24 fret necks, the 24th fret A string(5th).WOW! So on a 24 fret neck, there's 5 places to hit the same note! However the thing most people don't realize is that in each of those positions the note has a much different tone voicing, becoming brighter closer to the top of the neck and darker closer to the body.
However, 440Hz is the standard tuning note for all instruments. This is the A note you hear large orchestras tuning to. But basically, the rule is that the frequency of a note doubles every octave. So 110Hz being the low A, the middle A on the second fret G and the 7th fret D, or the 12th fret A is 220Hz, and the next one up is 440Hz.
So on a 24 fret guitar, the highest E note would be 1318.56Hz, or 1.3KHz, so this means that boosting any frequencies above that won't make a difference right?
Jon
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